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  3. Ratio & Proportion
Ratio & Proportion

Rates and Unit Rates: Speed, Best Buys and Per-One Comparisons

What makes a rate different from a ratio, how to find a unit rate, the speed–distance–time relationship, and how unit prices settle which deal is better.

3 min read Supports 3 lessons
In short

A rate compares two quantities measured in different units, such as 150150150 km in 333 hours. A unit rate scales it to one of the second quantity: 505050 km per hour.

A ratio compares quantities of the same kind, like cups to cups. A rate compares quantities of different kinds: kilometres per hour, pounds per kilogram, words per minute, beats per second.

The most useful form is the unit rate, which tells you how much of one quantity goes with one of the other. The word to listen for is per, which means "for each".

150 km3 h=50 km1 h=50 km/h\frac{150 \text{ km}}{3 \text{ h}} = \frac{50 \text{ km}}{1 \text{ h}} = 50 \text{ km/h}3 h150 km​=1 h50 km​=50 km/h

Divide both quantities by the same number until the second one is 1.

Speed, distance and time

Speed is the rate at which distance is covered. Rearranging the same relationship gives distance and time too.

Speed, distance, time
speed=distancetimedistance=speed×timetime=distancespeed\text{speed} = \frac{\text{distance}}{\text{time}} \qquad \text{distance} = \text{speed} \times \text{time} \qquad \text{time} = \frac{\text{distance}}{\text{speed}}speed=timedistance​distance=speed×timetime=speeddistance​

At a steady 505050 km/h, distance grows by 505050 every hour. The unit rate is the slope of this line.

Watch out

Keep the units consistent. 909090 km in 454545 minutes is 90÷0.75=12090 \div 0.75 = 12090÷0.75=120 km/h, not 222 km/h. Convert minutes to hours first.

Best buys

Shops sell the same thing in different sizes. Dividing price by quantity gives the unit price, and the lower unit price is the better deal.

  1. 6 apples for £2.40or10 apples for £3.806 \text{ apples for } £2.40 \quad\text{or}\quad 10 \text{ apples for } £3.806 apples for £2.40or10 apples for £3.80

    Which is better value?

1/4
Tip

You can divide the other way, too: apples per pound. Then the higher number is the better deal. Just be clear which way round you went.

Using a unit rate

Once you have the rate for one, multiply to get any amount you like. This is often called the unitary method.

Worked example

A printer prints 848484 pages in 666 minutes. How many pages in 151515 minutes?

  1. 1

    Unit rate.

    84÷6=14 pages per minute84 \div 6 = 14 \text{ pages per minute}84÷6=14 pages per minute
Key idea

A constant rate is the slope of a straight-line graph. When the rate changes, as with a car speeding up, calculus measures the rate at each instant.

Common questions

What is the difference between a rate and a ratio?

A ratio compares quantities of the same kind, like boys to girls. A rate compares different kinds of quantity, like kilometres to hours, so it always has units.

How do I find a unit rate?

Divide the first quantity by the second. £3.80£3.80£3.80 for 101010 apples gives 3.80÷10=£0.383.80 \div 10 = £0.383.80÷10=£0.38 per apple.

Practise rates and unit rates

The Rates & Unit Rates lesson has worked examples and unlimited practice that adapts to you.

Open the lesson

On this page

  1. Speed, distance and time
  2. Best buys
  3. Using a unit rate
  4. Common questions
Lessons on this
  • Rates & Unit RatesRatios & Proportions
  • ProportionsRatios & Proportions
  • Average Rate of ChangeFunctions
Related reading5
Ideas this article builds on or leads to.
  • Ratio & Proportion
    Ratios Explained: Simplifying and Sharing in a Ratio

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  • Ratio & Proportion
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  • Ready for Calculus
    Average Rate of Change and the Secant Line

    The average rate of change of a function between x=ax = ax=a and x=bx = bx=b is the change in output divided by the change in input, f(b)−f(a)b−a\frac{f(b) - f(a)}{b - a}b−af(b)−f(a)​. It is the slope of the secant line joining the two points.

  • Algebra
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    Rearranging a formula means making a different letter its subject, the letter on its own on one side. You use the same balancing steps as solving an equation, treating the other letters as if they were numbers.